Example 1 :
Device A: 172.16.17.30/20
Device A: 172.16.17.30/20
Device B: 172.16.28.15/20
Determining the Subnet for Device A:
172.16.17.30 - 10101100.00010000.00010001.00011110
255.255.240.0 -
11111111.11111111.11110000.00000000
-----------------| sub|------------
subnet =
10101100.00010000.00010000.00000000 = 172.16.16.0
Determining the Subnet for Device B:
172.16.28.15 -
10101100.00010000.00011100.00001111
255.255.240.0 - 11111111.11111111.11110000.00000000
-----------------|
sub|------------
subnet = 10101100.00010000.00010000.00000000 =
172.16.16.0
Example 2 :
Network ID: 192.168.1.0
SubNet MASK : 255.255.255.0
New SubNet MASK : 255.255.255.128
Bits Borrowed : 192.168.1.1|0000000
# Of possible networks: 2
Solution :
SubNetwork 1: 192.168.1.0
First valid IP: 192.168.1.1
Last valid IP: 192.168.1.126
Broadcast: 192.168.1.127
SubNetwork 2: 192.168.1.128
First valid IP: 192.168.1.129
Last valid IP: 192.168.1.254
Broadcast: 192.168.1.255
No comments:
Post a Comment